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Sagot :
Answer:
I think its C
Step-by-step explanation:
Because if you add the bottom together you get [tex]\frac{1}{\frac{1}{2x+5} }[/tex]. When you divide the bottom part flips so it would be [tex]1*2x+5[/tex] which ends up being C
I think this is right but I may be wrong
Answer:
B
Step-by-step explanation:
Simplify the sum on the denominator, that is
[tex]\frac{1}{x+2}[/tex] + [tex]\frac{1}{x+3}[/tex]
multiply numerator/ denominator of first fraction by x + 3
Multiply numerator/ denominator of second fraction by x+ 2
= [tex]\frac{x+3}{(x+2)(x+3)}[/tex] + [tex]\frac{x+2}{(x+2)(x+3)}[/tex]
= [tex]\frac{2x+5}{x^2+5x+6}[/tex]
The original fraction is now
[tex]\frac{1}{\frac{2x+5}{x^2+5x+6} }[/tex]
= 1 × [tex]\frac{x^2+5x+6}{2x+5}[/tex]
= [tex]\frac{x^2+5x+6}{2x+5}[/tex] → B
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