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Let x represents a length in cm where x > 1.5.
AB = 2x - 3, BC = 4x – 6,
AD = 2x + 3 and BE = 4x +1
• ABC is right triangle of area Sı.
. CBFG is a rectangle of area S2.
• ADEB is a right trapezoid of area S3.
1) Express S1, S2 and S3 in terms of x.
2) Let S = S1 + S2 -S3.​

Let X Represents A Length In Cm Where X Gt 15AB 2x 3 BC 4x 6AD 2x 3 And BE 4x 1 ABC Is Right Triangle Of Area Sı CBFG Is A Rectangle Of Area S2 ADEB Is A Right class=

Sagot :

Answer:

1) S1 = 4·x² - 12·x + 9

S2 = 12·x² - 26·x + 12

S3 = 6·x² - 5·x - 6

2) S = 10·x² - 33·x + 27

Step-by-step explanation:

The length x in cm > 1.5

Segment AB = 2·x - 3, segment BC = 4·x - 6, segment AD = 2·x + 3 and segment BE = 4·x + 1

1) a) The area of the right triangle ABC = S1 = 1/2 × Base × Height

The base of the triangle ABC = Segment BC = 4·x - 6

The height of the triangle ABC = Segment AB = 2·x - 3

Therefore, The area of the triangle ABC = S1 = 1/2 × (4·x - 6) × (2·x - 3) = 1/2 × (8·x² - 12·x - 12·x + 18) = 4·x² - 12·x + 9

S1 = 4·x² - 12·x + 9

b) The area of the rectangle CBFG = S2 = Base × Height

The base of the rectangle CBFG = BC = 4·x - 6

The height of the rectangle CBFG = BF = 3·x - 2

The area of the rectangle CBFG = S2 =(4·x - 6) × (3·x - 2) = 12·x² - 8·x - 18·x + 12

The area of the rectangle CBFG = S2 = 12·x² - 26·x + 12

S2 = 12·x² - 26·x + 12

c) The area of the trapezoid ADEB = S3 = 1/2 × (Long side + Short side) × The height of the trapezoid ADEB

The long side of the trapezoid ADEB = BE = 4·x + 1

The short side of the trapezoid ADEB = AD = 2·x + 3

The height of the trapezoid ADEB = AB = 2·x - 3

The area of the trapezoid ADEB = S3 = 1/2 × (4·x + 1 + 2·x + 3) × (2·x - 3) = 6·x² - 9·x + 4·x - 6

∴ The area of the trapezoid ADEB = S3 = 6·x² - 5·x - 6

S3 = 6·x² - 5·x - 6

2) S = S1 + S2 - S3 = 4·x² - 12·x + 9 + 12·x² - 26·x + 12 - (6·x² - 5·x - 6) = 10·x² - 33·x + 27

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