IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Find the answers you need quickly and accurately with help from our knowledgeable and experienced experts.

How many different phone numbers are possible in the area code 503, if the first number cannot start with a 0 or 1

Sagot :

Answer:

8 X 10^(9)

Step-by-step explanation:

Originally we have 10 digit phone numbers excluding the area code.

For each face value we have these in store: 0,1,2,3,4,5,6,7,8,9 (total 10)

But if we exclude 1 and 0 for the first digit, we are left with 8 digits.

8P1 X .......

In a phone number, digits can repeat so we can choose out of these 10 numbers freely after this.

8P1 X 10P1 X 10P1 X...

Adding the area code while assuming 10P1 is just 10...we get:

1 X 1 X 1 X 8 X 10^(9)

= 8000000000

Very interesting question, thanks for the opportunity!

The number of  different phone numbers in the area code 503, if the first number cannot start with a 0 or 1 should be considered as the [tex]8 \times 10^{(9)}[/tex]

Calculation of the number of different phone numbers:

Since

we have 10 digit phone numbers that does not include the area code.

So,

For each face value we have these in store:

0,1,2,3,4,5,6,7,8,9 (total 10)

Now

if we exclude 1 and 0 for the first digit, So it left with 8 digits.

So, it be like

8P1 X .......

Likewise

8P1 X 10P1 X 10P1 X...

Now if add this,

1 X 1 X 1 X 8 X 10^(9)

= 8000000000

hence, The number of  different phone numbers are possible in the area code 503, if the first number cannot start with a 0 or 1 should be considered as the [tex]8 \times 10^{(9)}[/tex]

Learn more about number here: https://brainly.com/question/11318214

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.