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Sagot :
Answer:
Following are the solution to this question:
Step-by-step explanation:
[tex]\to tellurium-131\\\\ \to T(t) =1000 \times e^{\frac{\log(2)}{25}t}[/tex]
where t = in miles
In part A:
When scientists got t=0, therefore the tellurium quantity.
[tex]\to T(t) = 1000 \times e^{0}[/tex]
[tex]= 1000 \times 1 \\\\= 1000 \ grams[/tex]
In part B:
When 1 hours = 60 min
[tex]T(t) = 1000 \times e^{\frac{\log 2}{25} \times 60} \\\\[/tex]
[tex]= 1000 \times e^{\frac{\log 2}{5} \times 12}\\\\= 1000 \times e^{0.72247199}\\\\\= 1000 \times 2.05951803\\\\=2059.51803\\\\=2059.51 \ grams[/tex]
Task Radioactive isotopes decay by emitting radiation is that :
A) The tellurium-131 were in the sample the moment the scientist received are 1000 grams.
B)The grams of tellurium-131 will remain in the sample after one hour is 2059.51.
Given :
- Tellurium-131
- T(t)=100*[tex]e^{log2/25} t[/tex]
- where t = in miles
Part A:
When scientists got t=0,
t=1000*[tex]e^{o}[/tex]
t=1000*1
t=1000 grams
The tellurium-131 were in the sample the moment the scientist received are 1000 grams.
Part B:
The grams of tellurium-131 will remain in the sample after one hour is :
- T(t)=1000*[tex]e^{log2/25} t[/tex]
- T(t)=1000*[tex]e^{0.7224}[/tex]
- T(t)=1000*2.059
- T(t)= 2059.51
The grams of tellurium-131 will remain in the sample after one hour is 2059.51.
Know more about "isotopes":
https://brainly.com/question/13214440?referrer=searchResults
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