IDNLearn.com offers a reliable platform for finding accurate and timely answers. Our platform offers reliable and detailed answers, ensuring you have the information you need.
Sagot :
Answer:
Following are the solution to this question:
Step-by-step explanation:
[tex]\to tellurium-131\\\\ \to T(t) =1000 \times e^{\frac{\log(2)}{25}t}[/tex]
where t = in miles
In part A:
When scientists got t=0, therefore the tellurium quantity.
[tex]\to T(t) = 1000 \times e^{0}[/tex]
[tex]= 1000 \times 1 \\\\= 1000 \ grams[/tex]
In part B:
When 1 hours = 60 min
[tex]T(t) = 1000 \times e^{\frac{\log 2}{25} \times 60} \\\\[/tex]
[tex]= 1000 \times e^{\frac{\log 2}{5} \times 12}\\\\= 1000 \times e^{0.72247199}\\\\\= 1000 \times 2.05951803\\\\=2059.51803\\\\=2059.51 \ grams[/tex]
Task Radioactive isotopes decay by emitting radiation is that :
A) The tellurium-131 were in the sample the moment the scientist received are 1000 grams.
B)The grams of tellurium-131 will remain in the sample after one hour is 2059.51.
Given :
- Tellurium-131
- T(t)=100*[tex]e^{log2/25} t[/tex]
- where t = in miles
Part A:
When scientists got t=0,
t=1000*[tex]e^{o}[/tex]
t=1000*1
t=1000 grams
The tellurium-131 were in the sample the moment the scientist received are 1000 grams.
Part B:
The grams of tellurium-131 will remain in the sample after one hour is :
- T(t)=1000*[tex]e^{log2/25} t[/tex]
- T(t)=1000*[tex]e^{0.7224}[/tex]
- T(t)=1000*2.059
- T(t)= 2059.51
The grams of tellurium-131 will remain in the sample after one hour is 2059.51.
Know more about "isotopes":
https://brainly.com/question/13214440?referrer=searchResults
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.
