Answer:
The correct answer is -50%
Explanation:
Polydactyly is a dominant trait where a person gets an extra finger or toes the dominant allele is represented by P = allele for polydactyly, and the recessive allele represented by p = normal allele
So, the heterozygous woman will be - Pp & the normal man will be - pp. The presence of one allele of polydactyly will be able to show its effect as it is dominant.
Cross between heterozygous woman & normal man:
Gametes:
P p
p Pp (Show polydactyly) pp (Normal phenotype)
p Pp (Show polydactyly) pp (Normal phenotype)
From the above Punnett square, the probability of an offspring that has extra fingers or toes will be 1/2 or 50%.
Polydactyly is a condition that occurs wherein individuals have more than the normal amount of fingers and toes. It is also a genetic condition and as well heritable.
The probability of producing an offspring with extra toes or fingers in a cross between an heterozygous and a normal is 50%.
Let P represent the dominant and p the recessive
Pp (heterozygous) and pp (normal)
(woman) P p
(man) p Pp pp
p Pp pp
50% 50%
Therefore, the probability of producing an offspring with extra toes or fingers (Pp) is 50%.
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