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9x2+4y2 = 36
The foci are located at:
O(-V5,0) and (V5, 0)
0 (-V13, 0) and (V13, 0)
0 (0, -V5) and (0, V5)


Sagot :

Answer:

The foci of the given ellipse  = (0 ,-√5 ) and ( 0, √5 )

Step-by-step explanation:

Step(i):-

Given Ellipse   9 x² + 4 y² = 36

                     [tex]\frac{9x^{2} }{36} + \frac{4y^{2} }{36} =1[/tex]

               ⇒     [tex]\frac{x^{2} }{4} + \frac{y^{2} }{9} = 1[/tex]

Step(ii):-

  The Major axis lies on y-axis

   Foci of the Formula C² = a² -b² = 9-4 =5

                                 C = √5

The Foci is always lie on the major axis(longest) axis, spaced equally each side of the centre

Given ellipse of the foci is lie on Y- axis

Final answer:-

The foci of the given ellipse  = (0 ,-√5 ) and ( 0, √5 )