Answered

IDNLearn.com provides a platform for sharing and gaining valuable knowledge. Discover in-depth and trustworthy answers from our extensive network of knowledgeable professionals.

is
A 0.155 kg arrow is shot upward
at 31.4 m/s. What is its kinetic
energy (KE) when it is 30.0 m
above the ground?

Sagot :

Ardni313idn

Kinetic energy = 29.912 J

Further explanation

Given

mass = 0.155 kg

vo=initial velocity = 31.4 m/s

h/d=30 m

Required

KE=kinetic energy

Solution

vt²=vo²-2ad⇒vt=final velocity

vt²=31.4²-2.10.30⇒g=10 m/s²

vt²=985.96-600

vt²=385.96 m/s

Kinetic  energy (KE)

[tex]\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 0.155.\times 385.96\\\\KE=29.912~J[/tex]

Answer:

The answer is 30.8 (J)

Explanation:

You're welcome

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.