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proove that
1/1-sin theta + 1/1+cos theta = 2×sec square theta ​

Sagot :

Abidemiokinidn

Answer:

Step-by-step explanation:

We are to show that 1/1-sin theta + 1/1+cos theta = 2×sec square theta ​

Starting from the left hand side of the expression:

1/1-sin theta + 1/1+cos theta

Find the LCM

[tex]\frac{1}{(1 -sin \theta) (1+cos \theta)} \\\\= \frac{1+cos \theta + 1 -sin \theta ]}{(1 -sin \theta) (1+cos \theta)} \\ = \frac{2+cos \theta - sin \theta}{1+cos \theta - sin \theta - sin \theta cos \theta}[/tex]

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