Answered

Get the information you need with the help of IDNLearn.com's expert community. Join our knowledgeable community and get detailed, reliable answers to all your questions.

Type the correct answer in the box. Use numerals instead of words.
Adrian has a bag full of pebbles that all look about the same. He weighs some of the pebbles and finds that their weights are normally distributed, with a mean of 2.6 grams and a standard deviation of 0.4 grams.

What percentage of the pebbles weigh more than 2.1 grams? Round to the nearest whole percent.

Sagot :

Absor201idn

Answer:

89% of pebbles weigh more than 2.1 grams.

Step-by-step explanation:

Given that

Mean = 2.6

SD = 0.4

As we have to find the percentage of pebbles weighing more than 2.1, we have to find the z-score for 2.1 first

[tex]z = \frac{x-mean}{SD}\\z = \frac{2.1-2.6}{0.4}\\z = -1.25[/tex]

Now we have to use the z-score table to find the percentage of pebbles weighing less than 2.1

So,

[tex]P(x<-1.25) = 0.10565[/tex]

This gives us the probability of P(z<-1.25) or P(x<2.1)

To find the probability of pebbles weighing more than 2.1

[tex]P(x>2.1) = 1 - P(x<2.1) = 1 - 0.10565 = 0.89435[/tex]

Converting into percentage

[tex]0.89435*100 = 89.435\%[/tex]

Rounding off to nearest percent

89%

Hence,

89% of pebbles weigh more than 2.1 grams.

Answer:

89%

Step-by-step explanation:

View image Sarahalohilani
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.