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13 Here is information about the age, in years, of each of Jelina's five children when written
in order
a
b
b/2+ a
2b + a +3
2b + a +5

It is given that
a is the age of the youngest child
a≠b
two of the children have the same age
the mean age of the five children is 10.6
Calculate the value of a and the value of b
Show clear algebraic working.


Sagot :

Answer:

a)x-1 by 4=3

b)3x+6 by 2=3 by 2

c)3x-1by5=2x+3by7

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