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Answer:
The number of moles of the air is 4.464 x 10⁻⁴ mole
The number of molecules is 2.688 x 10²⁰ molecules
Explanation:
Given;
pressure of the air, P = 1 atm
volume of the air, V = 1 m³
temperature of the air, T = 0° C = 273 K
The number of moles of the air is calculated as;
PV = nRT
[tex]n = \frac{PV}{RT}[/tex]
where;
n is the number of moles
R is ideal gas constant = 8.2057m³atm/mol.k
[tex]n = \frac{1atm \ \times \ 1m^3}{(8.2057 \ m^3 atm/mol.K)(273 \ K)} = 4.464 \ \times 10^{-4} \ mol.[/tex]
The number of molecules is calculated as follows;
1 mole ---------------------> 6.022 x 10²³ molecules
4.464 x 10⁻⁴ mole ----------> ?
= (4.464 x 10⁻⁴) (6.022 x 10²³ molecules)
= 2.688 x 10²⁰ molecules of air.