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An object falls from a high building. Ignoring air resistance, what will its velocity be after 6 seconds of falling

Sagot :

Evasiwilaidn

Explanation:

Vf=Vi+at

reference frame,take down as positive in y- axis

Data

Vi=0m/s

Vf=?

a=g(9.8m/s2)

t=6s

Vf=0+9.8m/s2*6s

Vf=58.8m/s

Eduard22slyidn

The velocity of the object after falling for 6 s from a high building is 58.8 m/s

  • From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Time (t) = 6 s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

  • The velocity of the object after falling for 6 s can be obtained as follow:

v = u + gt

v = 0 + (9.8 × 6)

v = 0 + 58.8

v = 58.8 m/s

Therefore, the velocity of the object after falling for 6 s is 58.8 m/s

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