Miningdiamonds6969idn
Answered

From simple questions to complex issues, IDNLearn.com has the answers you need. Discover comprehensive answers from knowledgeable members of our community, covering a wide range of topics to meet all your informational needs.

Given z1=9+9sqrt(3)i and z2=2+sqrt(3)i what is z2-z1
This is urgent will give brainliest!

Sagot :

Answer:

[tex] = 2 + \sqrt{3} i - (9 + 9 \sqrt{3} i) \\ = (2 - 9) + ( \sqrt{3} - 9 \sqrt{3} )i \\ = - 7 + (1 - 9) \sqrt{3} i \\ = - 7 - 8 \sqrt{3} i[/tex]

The required simplification of z2-z1 = -7-8sqrt(3)i.

z1=9+9sqrt(3)i
z2=2+sqrt(3)i
z2-z1 to be determined.

What is a complex number?

A complex number is defined as the sum of a real and imaginary numbers.

Here,
[tex]z_1=9+9\sqrt(3)i\\z_2=2+\sqrt(3)i\\\\z_2-z_1 = 2+\sqrt(3)i-(9+9\sqrt3i\\z_2-z_1 = 2-9+\sqrt(3)i-9\sqrt3i\\z_2-z_1 = -7-8\sqrt(3)i[/tex]

Thus, the required simplification of z2-z1 = -7-8sqr(3)i.


Learn more about complex numbers here:

https://brainly.com/question/28007020
#SPJ2

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.