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Drag and drop each pair of lines into the correct category to indicate whether the pair of lines are parallel, perpendicular, or neither.
1/7x + y = 9; y = -7x
y = 3x - 3; 12x - 4y = 12
7y = 2x + 1; 14x + 4y = 12
x - 4y = 18; y = x + 4
3x - 4y = -1; 3y = -4x + 5
Parallel Perpendicular Neither​

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Answer:

Step-by-step explanation:

(1). [tex]\frac{1}{7}[/tex] x + y = 9 and y = - 7x ( Neither ) ; lines intersect.

(2). y = 3x - 3; 12x - 4y = 12 ( Neither ) ; Lines are overlapped or both equation are of the same line.

(3). 7y = 2x + 1; 14x + 4y = 12 ( Perpendicular ) ; [tex]m_{1}[/tex] = [tex]\frac{2}{7}[/tex] and [tex]m_{2}[/tex] = - [tex]\frac{7}{2}[/tex] , slopes are opposite reciprocals.

(4). x - 4y = 18; y = x + 4 ( Neither ) ; lines intersect.

(5). 3x - 4y = - 1; 3y = - 4x + 5 ( Perpendicular ) ; [tex]m_{1}[/tex] = [tex]\frac{3}{4}[/tex] and [tex]m_{2}[/tex] = - [tex]\frac{4}{3}[/tex] , slopes are opposite reciprocals.

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