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Proove that: tanα + cotα = secα. cosecα

Sagot :

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

tan a = [tex]\frac{sina}{cosa}[/tex], cot a = [tex]\frac{cosa}{sina}[/tex]

sec a = [tex]\frac{1}{cosa}[/tex], cosec a = [tex]\frac{1}{sina}[/tex]

Consider the left side

tana + cota

= [tex]\frac{sina}{cosa}[/tex] + [tex]\frac{cosa}{sina}[/tex]

= [tex]\frac{sin^2a+cos^2a}{cosasina}[/tex]

= [tex]\frac{1}{cosasina}[/tex]

= [tex]\frac{1}{cosa}[/tex] × [tex]\frac{1}{sina}[/tex]

= seca . coseca

= right side , thus proven

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