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A car accidentally rolls off cliff as it leaves the cliff it has a horizontal velocity of 13 m/s it hits the ground 60 m from the shoreline calculate the height of the cliff

Sagot :

Answer:

h = 104.13 m

Explanation:

Given that,

Horizontal velocity of the car, v = 13 m/s

It hits the ground 60 m from the shoreline

We need to find the height of the cliff. Let t be the time of fall. We can find it as follows :

[tex]t=\dfrac{d}{v}\\\\t=\dfrac{60\ m}{13\ m/s}\\\\t=4.61\ s[/tex]

So, the time of fall is 4.61 seconds.

Let h is the height of the cilff. Using second equation of motion to find it as follows :

[tex]h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times 4.61^2\\\\=104.13\ m[/tex]

So, the height of the cliff is 104.13 m.

Eduard22slyidn

The height of the cliff from which the car rolls off is 104.59 m

We'll begin by calculating the the time taken for the car to reach the ground.

Horizontal distance (s) = 60 m

Horizontal velocity (u) = 13 m/s

Time (t) =?

[tex]t = \frac{s}{u} \\ \\ t = \frac{60}{13} \\ [/tex]

t = 4.62 s

Thus, the time taken for the car to reach the ground is 4.62 s

  • Finally, we shall determine the height of the cliff.

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 4.62²

h = 104.59 m

Therefore, the height of the cliff is 104.59 m

Learn more: https://brainly.com/question/15206806

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