Answered

IDNLearn.com provides a collaborative environment for finding and sharing knowledge. Discover comprehensive answers to your questions from our community of experienced professionals.

D(n) = \dfrac{5}{16} \left(2\right)^{n - 1}d(n)= 16 5 ​ (2) n−1 d, left parenthesis, n, right parenthesis, equals, start fraction, 5, divided by, 16, end fraction, left parenthesis, 2, right parenthesis, start superscript, n, minus, 1, end superscript What is the 5^\text{th}5 th 5, start superscript, start text, t, h, end text, end superscript term in the sequence?

Sagot :

Answer:

d(5) = 5

Step-by-step explanation:

The nth term is given by :

[tex]d(n)=\dfrac{5}{16}\times 2^{n-1}[/tex] ...(1)

We need to find the 5th term of the above sequence. For this, put n = 5 in the above formula.

[tex]d(5)=\dfrac{5}{16}\times 2^{5-1}\\\\=\dfrac{5}{16}\times 2^4\\\\=\dfrac{5}{16}\times 16\\\\=5[/tex]

So, the 5th term in the above sequence is 5.

Jiaojason2020idn

Answer:

5

Step-by-step explanation

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.