Answer: 3x^2+4x-2
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Explanation:
Assume the polynomial we want to find is in the form Ax^2+Bx+C
The goal is to find the values of A, B, and C.
We start with 3x^2+4x-1, then we subtract off Ax^2+Bx+C. Set this equal to 1 and we get:
(3x^2+4x-1) - (Ax^2+Bx+C) = 1
3x^2+4x-1 -Ax^2-Bx-C = 0x^2 + 0x + 1
(3x^2-Ax^2) + (4x-Bx) + (-1-C) = 0x^2 + 0x + 1
(3-A)x^2 + (4-B)x + (-1-C) = 0x^2 + 0x + 1
From here we equate the coefficients of the x^2 terms together and we see that 3-A = 0 which leads to A = 3.
Do the same for the x terms to get 4-B = 0 leading to B = 4
Finally, we have -1-C = 1 lead to C = -2
The polynomial Ax^2+Bx+C becomes 3x^2+4x-2
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Checking the answer:
(3x^2+4x-1) - (Ax^2+Bx+C)
(3x^2+4x-1) - (3x^2+4x-2)
3x^2+4x-1 - 3x^2-4x+2
(3x^2-3x^2) + (4x-4x) + (-1+2)
0x^2 + 0x + 1
0 + 0 + 1
1
We get a difference of 1, so the answer is confirmed.
