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Find the equation of the line that is perpendicular to the given line and passes through the given point. Enter your answer in slope intercept for (y=mx+b) with the values of m and b given as decimals, rounded to the nearest hundredth if necessary. y=20x;(2,2)
The equation is y =
Please help very urgent! :)

Find The Equation Of The Line That Is Perpendicular To The Given Line And Passes Through The Given Point Enter Your Answer In Slope Intercept For Ymxb With The class=

Sagot :

Answer:

y = - 0.05x - 1.9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

y = 20x ← is in slope- intercept form

with slope m = 20

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{20}[/tex] = - 0.05 , thus

y = - 0.05x + b ← is the partial equation

To find b substitute (2, - 2) into the partial equation

- 2 = - 0.1 + b ⇒ b = - 2 + 0.1 = - 1.9

y = - 0.05x - 1.9 ← equation of perpendicular line

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