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Answer:
a) 4.58m/s²
b) 10.454N
Explanation:
According to Newton second law, the following simultaneous equation will be applicable
T - Fm = m1a.... 1
W - T = m2a ....2
m1 and m2 are the masses
T is the tension of the string
W is the weight of mass m2
Fm is the force acting along the incline
Fm = m1gsin theta
W = m2g
a) Add both equation to eliminate tension T
W-Fm = m1a+m2a
m2g - m1gsin theta = (m1+m2)a
Substitute the given values
2(9.8)-0.8(9.8)sin60 = (2+0.8)a
19.6-6.79 = 2.8a
12.81 = 2.8a
a = 12.81/2.8
a = 4.58m/s²
Hence the acceleration of the blocks is 4.58m/s2
b) Get the Tension T
Substitute the acceleration gotten in (a) into equation 1 as shown:
From 1:
T - Fm = m1a
T = m1a+Fm
T = 0.8(4.58)+m1gsintheta
T = 0.8(4.58)+0.8(9.8)sin60
T = 3.664+6.79
T = 10.454N
Hence the tension in the string is 10.454N