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Answer:
Following are the solution to this question:
Explanation:
Law:
[tex]\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}[/tex]
[tex]= 180^{\circ}- 75^{\circ}\\\\= 105^{\circ}[/tex]
[tex]\to \frac{T_{L}}{\sin (90+50)}= \frac{T_{R}}{\sin (25+90)}=\frac{1400}{\sin (105)}[/tex]
[tex]\to T_L=931.65 \ pounds \\\\ \to T_R=1313.59 \ pounds \\\\[/tex]
