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Answer:
The answer is "DACB".
Explanation:
The missing data of the question is defined in the attached file please find it.
Using formula:
[tex]\to F= m \cdot a\\\\ \to m= 5 \ kg[/tex]
In object A:
[tex]F= 15 \\\\a =\frac{F}{m} = \frac{15}{5} = 3[/tex]
In object B:
[tex]F= 30 \\\\a =\frac{F}{m} = \frac{30}{5} = 6[/tex]
In object C:
[tex]F= 20 \\\\a =\frac{F}{m} = \frac{20}{5} = 4[/tex]
In object D:
[tex]F= 0 \\\\a =\frac{F}{m} = \frac{0}{5} = 30[/tex]
That's why the answer is "DACB" .
