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For the reaction 2H 2 +O 2 2H 2 O calculate the percent yield if 860. of water is produced when 100. g of hydrogen react with an excess of oxygen?

Sagot :

Ardni313idn

The percent yield : 95%

Further explanation

Given

Reaction

2H₂+O₂ ⇒2H₂O

Required

The percent yield

Solution

mol of Hydrogen(as a limiting reactant) :

[tex]\tt \dfrac{100}{2}=50[/tex]

mol H₂O based on H₂ , and from equation mol ratio H₂:H₂O=2 : 2, so mol H₂O = 50

Mass of water(theoretical yield) :

[tex]\tt mass=50\times 18=900~g[/tex]

[tex]\tt \%yield=\dfrac{860}{900}\times 100\%=95\%[/tex]

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