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Sagot :
Answer:
[tex]\large\boxed{\pink{ \leadsto The \ given \ equation \ is \ not \ a \ Quadratic \ equation . }}[/tex]
Step-by-step explanation:
Given equation to us is ,
[tex]\green{\implies x^2+\dfrac{1}{x}=4 }[/tex]
So , a equation is said to be a quadratic equation if the highest degree of the variable is 2 . On simplifying the Equation ,
[tex]\implies x^2 +\dfrac{1}{x}=4 [/tex]
Taking x as LCM ,
[tex]\implies \dfrac{x^2.x + 1 }{x}= 4 [/tex]
Transposing x to RHS .
[tex]\implies x^3 + 1 = 4x [/tex]
Putting all terms in LHS
[tex]\boxed{\bf \implies x^3 - 4x - 1 = 0 }[/tex]
Since here the highest degree of the variable is 3 not 2 . So its a cubic equation and not a quadratic equation .
Hence the given equation is not a quadratic equation .
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