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Which of the following is the equation of an ellipse centered at (4,-1) having a
horizontal minor axis of length 14 and a major axis of length 20?

Which Of The Following Is The Equation Of An Ellipse Centered At 41 Having A Horizontal Minor Axis Of Length 14 And A Major Axis Of Length 20 class=

Sagot :

Answer:

B for me

Step-by-step explanation:

Yun lang po correct me if iam wrong

The Required equation for the ellipse is given by   [tex]\frac{(x-4)^2}{49}+\frac{y+1}{100} = 1[/tex] Option B. is correct

What is an ellipse?

Ellipse is cross-section part of a cone structure when cutting it out a horizontal cross-section of a cone.

(x-h)^2/a^2 + (x-k)^2/b^2 = 1
(h,k) = centre of the ellipse.
a, b = semi minor or major axis,

[tex]\frac{(x-4)^2}{49}+\frac{y+1}{100} = 1[/tex]

thus, the required equation of ellipse is given by [tex]\frac{(x-4)^2}{49}+\frac{y+1}{100} = 1[/tex].

Learn more about ellipse here:
https://brainly.com/question/14281133

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