Answered

Discover new perspectives and gain insights with IDNLearn.com. Our community is here to provide detailed and trustworthy answers to any questions you may have.

help please, will give brainliest!
A. the equation has two true solutions
B. the equation had one true solution
C. the equation has one extraneous solution
D. the equation has one true solution and one extraneous solution ​

Help Please Will Give BrainliestA The Equation Has Two True Solutions B The Equation Had One True Solution C The Equation Has One Extraneous Solution D The Equa class=

Sagot :

Mhanifaidn

Answer:

  • C. the equation has one extraneous solution

Step-by-step explanation:

Given equation:

  • x/(x - 1) + 2/(x + 2) = -6/(x² + x - 2)

Common denominator is x² + x - 2, consider x ≠ 1 and x≠ -2

Multiply both sides by x² + x - 2:

  • x(x + 2) + 2(x - 1) = -6
  • x² + 2x + 2x - 2 + 6 = 0
  • x² + 4x + 4 = 0
  • (x + 2)² = 0
  • x + 2 = 0
  • x = -2

There is one solution but it is not true one.

Option C is correct

Manissaha129idn

Answer:

[tex] \frac{x}{x - 1} + \frac{2}{x + 2} = \frac{ - 6}{ {x}^{2} + x - 2 } \\ \frac{x(x + 2) + 2(x - 1)}{(x - 1)(x + 2)} = \frac{ - 6}{ {x}^{2} + x - 2} \\ \frac{ {x}^{2} + 2x + 2x - 2 }{ {x}^{2} + 2x - x - 2} = \frac{ - 6}{ {x}^{2} + x - 2} \\ \frac{ {x}^{2} + 4x - 2 }{ {x}^{2} + x - 2} = \frac{ - 6}{ {x}^{2} + x - 2 } \\ {x}^{2} + 4x - 2 = - 6 \\ {x}^{2} + 4x + 4 = 0 \\ {x}^{2} + 2 \times 2 \times x + {2}^{2} = 0 \\ {(x + 2)}^{2} = 0 \\ x + 2 = 0 \\ \boxed{x = - 2 }[/tex]

x =-2 is the right answer.

C. the equation has one extraneous solution.

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.