Get the most out of your questions with the extensive resources available on IDNLearn.com. Get the information you need from our community of experts who provide accurate and comprehensive answers to all your questions.
Sagot :
Answer:
Concept: Sequences & Series
The hint here is to try to find the common factor, you asked us to solve 1 so see the solution below.
- 1,-3,9, -27 : We see a common base of 3 hence we can find that the series representation is
- [tex]( - 3) ^{n-1} [/tex]
Next we can find the next 3 terms by just plugging in the values
We want the 6th, 7th, and 8th term
So we plug 6 in for n and 7 in for n and 8 in for n
So we get the 6th term=-243
The 7th term= 729
The 8th term= -2187
Answer:
Step-by-step explanation:
1) 1 , -3 , 9 , -27 , 81 ,...........
It is Geometric sequence
ratio = 2 term ÷ first term = -3 ÷ 1 = -3
1st term = 1
2nd term = 1 * -3 = -3
3rd term = -3 *(-3) = 9
4th term = 9 *(-3) = - 27
6th term = 81 *(-3) = -243
7th term = -243 *(-3) = 729
8th term = 729 *(-3) = -2187
Next 3 terms: - 243 , 729 , - 2187,....
4)
[tex]\frac{1}{2}, \frac{1}{2} , \frac{3}{8} , \frac{1}{4} ,\frac{5}{32},.....\\\\\\Rule = \frac{n}{2^{n}}\\Term1 = \frac{1}{2^{1}}=\frac{1}{2}\\\\Term2 = \frac{2}{2^{2}}=\frac{2}{4}=\frac{1}{2}\\\\Term3 = \frac{3}{2^{3}}=\frac{3}{8}\\\\Term4 = \frac{4}{2^{4}}=\frac{4}{16}=\frac{1}{4}\\\\Temr5 = \frac{5}{2^{5}}=\frac{5}{32}\\\\Term6 = \frac{6}{2^{6}} = \frac{6}{64} = \frac{3}{32}\\\\Term7 = \frac{7}{2^{7}}=\frac{7}{128}\\\\Term8 =\frac{8}{2^{8}} = \frac{8}{256}=\frac{1}{32}\\\\[/tex]
Next 3 terms are : 3/32 , 7/128 , 1/32
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.