Experience the convenience of getting your questions answered at IDNLearn.com. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.
Sagot :
Answer:
The work done by friction was [tex]-4.5\times10^{5}\ J[/tex]
Explanation:
Given that,
Mass of car = 1000 kg
Initial speed of car =108 km/h =30 m/s
When the car is stop by brakes.
Then, final speed of car will be zero.
We need to calculate the work done by friction
Using formula of work done
[tex]W=\Delta KE[/tex]
[tex]W=K.E_{f}-K.E_{i}[/tex]
[tex]W=\dfrac{1}{2}mv_{f}^2-\dfrac{1}{2}mv_{f}^2[/tex]
Put the value of m and v
[tex]W=0-\dfrac{1}{2}\times1000\times(30)^2[/tex]
[tex]W=-450000 \ J[/tex]
[tex]W=-4.5\times10^{5}\ J[/tex]
Hence, The work done by friction was [tex]-4.5\times10^{5}\ J[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.
