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Answer:
[tex]Length = 41\frac{7}{16}[/tex]
Step-by-step explanation:
Given
[tex]Width = 8\frac{1}{2}[/tex]
[tex]Length = 4\frac{7}{8}[/tex] times as long as the width
Required
Determine the length
To do this, we simply multiply the length by [tex]4\frac{7}{8}[/tex]
So, we have:
[tex]Length = 4\frac{7}{8} * Width[/tex]
Substitute [tex]8\frac{1}{2}[/tex] for width
[tex]Length = 4\frac{7}{8} * 8\frac{1}{2}[/tex]
Convert to improper numbers
[tex]Length = \frac{39}{8} * \frac{17}{2}[/tex]
[tex]Length = \frac{39*17}{8*2}[/tex]
[tex]Length = \frac{663}{16}[/tex]
[tex]Length = 41\frac{7}{16}[/tex]