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Write a real-world problem where you would

want to compare rates of change for two different functions.


Sagot :

Answer and Step-by-step explanation:

Let us assume two boys are jogging.

Boy 1 jogging speed is 10 kilometres per hour

Boy 2 jogging speed is 20 kilometres per hour

This can be represented in terms of distance, d and time, t. When we do this, we have:

d = 10t boy 1

d = 20t boy 2

This implies that boy 1 rate of change is 10 kilometers for every one hour and boy 2 is 20 kilometers for every 1 hour.

From here, we can conclude that the rate of change of boy 2 is twice the rate of change of boy 1.