IDNLearn.com: Your destination for reliable and timely answers to any question. Our experts provide accurate and detailed responses to help you navigate any topic or issue with confidence.

The daily output at a plant manufacturing chairs is

approximated by the function

f(L,K) = 453KL 3/5 chairs

where L is the size of the labor force measured in hundreds

of worker-hours and K is the daily capital investment in

thousands of dollars. If the plant manager has a daily budget

of $13,000 and the average wage of an employee is $9.00

per hour, what combination of worker-hours (to the nearest

hundred) and capital expenditures (to the nearest thousand)

will yield maximum daily production?


Sagot :

Complete Question

The daily output at a plant manufacturing chairs is  approximated by the function

[tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex] chairs

where L is the size of the labor force measured in hundreds

of worker-hours and K is the daily capital investment in  thousands of dollars. If the plant manager has a daily budget  of $13,000 and the average wage of an employee is $9.00  per hour, what combination of worker-hours (to the nearest  hundred) and capital expenditures (to the nearest thousand)  will yield maximum daily production?

a)200 worker-hours and $9000 in capital expenditure

b)1100 worker-hours and $3000 in capital expenditure

c)500 worker-hours and $8000 in capital expenditure

d)900 worker-hours and $5000 in capital expenditure

e)600 worker-hours and $6000 in capital expenditure

f)300 worker-hours and $10,000 in capital expenditure

Answer:

d)900 worker-hours and $5000 in capital expenditure

Step-by-step explanation:

From the question we are told that

Daily output at a plant manufacturing chairs is  approximated by the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]

Daily budget  of $13,000

Average wage of an employee is $9.00  per hour

a) Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to for (a)

Mathematically solving with L=200 K=9000

[tex]f(L=200,K=9000) = (45\sqrt[3]{9000})200^3^/^5[/tex]

[tex]f(L=200,K=9000) = 45*20.8*24[/tex]

[tex]f(L=200,K=9000) = 22464[/tex]

b)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to for (b)

Mathematically solving with L=1100 K=3000

[tex]f(L=1100,K=3000) = (45\sqrt[3]{3000})1100^3^/^5[/tex]

[tex]f(L=1100,K=3000) = 45*14.4*66.8[/tex]

[tex]f(L=1100,K=3000) = 43286.4[/tex]

c)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (c)

Mathematically solving with L=500 K=8000

[tex]f(L=500,K=8000) = (45*\sqrt[3]{8000})*500^3^/^5[/tex]

[tex]f(L=500,K=8000) = 45*20*41.63[/tex]

[tex]f(L=500,K=8000) =37467[/tex]

d)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (d)

Mathematically solving with L=900 K=5000

[tex]f(L=900,K=5000) = (45*\sqrt[3]{5000})*900^3^/^5[/tex]

[tex]f(L=900,K=5000) = 45*17.09*59.2[/tex]

[tex]f(L=900,K=5000) =45577.88[/tex]

e)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (e)

Mathematically solving with L=600 K=6000

[tex]f(L=600,K=6000) = (45\sqrt[3]{6000})600^3^/^5[/tex]

[tex]f(L=600,K=6000) = 45*18.17*46.4[/tex]

[tex]f(L=600,K=6000) =37974[/tex]

f)Generally the function  [tex]f(L,K) = 45\sqrt[3]{K}L^3^/^5[/tex]  can be use to find (e)

Mathematically solving with L=600 K=6000

[tex]f(L=300,K=10,000) = (45*\sqrt[3]{10,000})*300^3^/^5[/tex]

[tex]f(L=300,K=10,000) = 45*21.5*30.6[/tex]

[tex]f(L=300,K=10,000) = 29704.2[/tex]

Therefore the function f shows maximum at L=900 K=5000

Giving the correct answer to be

d)900 worker-hours and $5000 in capital expenditure