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solve for T: T/4+8>-10 A. T>72 B> T>-72 C. T T<-72

Sagot :

Gmanyidn

Answer:

[tex]\huge\boxed{B.\ T>-72}[/tex]

Step-by-step explanation:

[tex]\dfrac{T}{4}+8>-10\qquad|\text{subtract 8 from both sides}\\\\\dfrac{T}{4}+8-8>-10-8\\\\\dfrac{T}{4}>-18\qquad|\text{multiply both sides by 4}\\\\4\!\!\!\!\diagup\cdot\dfrac{T}{4\!\!\!\!\diagup}>(4)(-18)\\\\T>-72[/tex]

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