IDNLearn.com provides a collaborative environment for finding and sharing answers. Get the information you need from our community of experts who provide accurate and comprehensive answers to all your questions.

this is due today i would appreciate it a lot if smn could help me with it :/

This Is Due Today I Would Appreciate It A Lot If Smn Could Help Me With It class=

Sagot :

Answer:

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

Step-by-step explanation:

Function 1)

Determining rate of change for function 1:

x        1         2         3         4

y       5        8          11        14

Finding the rate of change or slope using the formula

Rate of change = m = [y₂-y₁] / [x₂-x₁]

Taking any two points, let say (1, 5) and (2, 8)

Rate of change = m = [8-5] / [2-1]

                                 = 3/1

                                  = 3

Therefor, the rate of change of function 1 = m = 3

using point-slope form to determine the function equation

y-y₁ = m (x-x₁)

where m is the rate of change or slope

substititng m = 3 and the point (1, 5)

y - 5 = 3(x - 1)

y - 5 = 3x-3

y = 3x-3+5

y = 3x + 2

Thus, equation of function 1 will be:

y = 3x + 2

Determining Initial Value for Function 1:

substituting x = 0 in the equation to determine the initial value

y = 3(0)+2

y = 0+2

y = 2

Therefore, the initial Value of function 1 will be: y = 2

Function 2)

Determining the rate of change for function 2:

Given the function 2

[tex]y\:=\:\frac{5}{3}x+3[/tex]

comparing with the slope-intercept form of a linear function

y = mx+b     where m is the rate of change

so the rate of change of function 2 = m = 5/3

Determining Initial Value for Function 2:

substituting x = 0 in the equation to determine the initial value

[tex]y\:=\:\frac{5}{3}x+3[/tex]

[tex]y\:=\:\frac{5}{3}\left(0\right)+3[/tex]

[tex]y = 0+3[/tex]

[tex]y = 3[/tex]

Therefore, the initial Value of function 2 will be: y = 3

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.