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A ball having a mass of 0.20 kilograms is placed at a height of 3.25 meters. If it is dropped from this height, what will be the kinetic energy of the ball when it reaches 1.5 meters above the ground?
A.
1.2 joules
B.
2.2 joules
C.
3.4 joules
D.
3.6 joules
E.
4.3 joules
Dk=Ww K’(when it’s in 1,5meters)-K(when it’s dropped)=mgdh K’-0(because it’s dropped,so u=0m/s)=mgdh K’=0.20*9.8*dh(dh=3.25-1.5=1.75 to find ball’s distance) K’=1,96*1.75=3.43 Joule The right answer is (c)
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