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1)The third equation must be halved. H20–>H2+1/2O2 So ΔΗ3=483.6/2 2)The second equation must be halved and reversed. CO2–>CO+1/2O2 So ΔΗ2=-(-566)/2=566/2
And now : C+O2–>CO2 CO2–>CO+1/2O2 H2O—>H2+1/2O2 (You add them) C+H2O—>CO+H2 ΔΗrxn=ΔΗ1+ΔΗ2’+ΔΗ3’=-393.5+283+241,8=131,3
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