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Answer:

Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex] results in a polynomial. After subtracting [tex]4x^2-3x[/tex] from this polynomial the difference is 14

Step-by-step explanation:

The question given is:

Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex] results in a polynomial. After subtracting [tex]4x^2-3x[/tex] from this polynomial the difference is?

First we will Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex]

[tex]7x^2+x+9-(3x^2+4x-5)\\=7x^2+x+9-3x^2-4x+5\\Combining\:like\:terms\\=7x^2-3x^2+x-4x+9+5\\=4x^2-3x+14[/tex]

So, the polynomial we get is: [tex]4x^2-3x+14[/tex]

Now, subtracting [tex]4x^2-3x\: from\: 4x^2-3x+14[/tex]

[tex]4x^2-3x+14-(4x^2-3x) \\=4x^2-3x+14-4x^2+3x\\Combining\:like\:terms\\=4x^2-4x^2-3x+3x+14\\=14[/tex]

The difference is 14

So, Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex] results in a polynomial. After subtracting [tex]4x^2-3x[/tex] from this polynomial the difference is 14

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