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An object with a mass of 32 kg has an initial energy of 500 J. At the end of the experiment, the velocity of the object is recorded as 5.1 m/s. If the object travelled 50 m to get to this point, what was the average force of friction on object during the trip? Assume no potential energy. Show all work
Explanation: the concept of conservation of the mechanical nerve initial Em₀ = 500 J The energy is totally kinetic Em₀ = K = ½ m v₀² v₀ = v₀ = √ (2 500/32) v₀ = 5.59 m / s v² = v₀² - 2 a x the negative sign is because its stopping a = a = (5.59² - 5.1²) / 2 50 a = 0.0524 m / s² Newton's second law F = ma F = 32 0.0524 F = 1.68 N
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