Find solutions to your questions with the help of IDNLearn.com's expert community. Join our Q&A platform to receive prompt and accurate responses from knowledgeable professionals in various fields.
Sagot :
Hi!
So, we need to find the inverse of the function f(x) = 15x - 7.
To start, we must turn the f(x) into a y.
y = 15x - 7.
Now, we swap all the x variables for the y variables, and swap all the y variables for the x variables!
x = 15y - 7.
Now, we simply must work on isolating y. Assuming you know how to isolate a variable, we must do the steps below -
x = 15y - 7.
Add 7 on both sides.
x + 7 = 15y - 7 + 7.
We cannot add x and 7, as they are not like terms. So, they will remain like that, while the 7 on the right side of the equation is eliminated.
x + 7 = 15y.
Now we are going to divide both sides by 15, thus leaving y by itself.
= 15y / 15.
Since we cannot divide the left side of the equation by 15, it will remain as such. With the y variable completely isolated, our final inverse function will be:
= .
Hopefully, this helps! =)
So, we need to find the inverse of the function f(x) = 15x - 7.
To start, we must turn the f(x) into a y.
y = 15x - 7.
Now, we swap all the x variables for the y variables, and swap all the y variables for the x variables!
x = 15y - 7.
Now, we simply must work on isolating y. Assuming you know how to isolate a variable, we must do the steps below -
x = 15y - 7.
Add 7 on both sides.
x + 7 = 15y - 7 + 7.
We cannot add x and 7, as they are not like terms. So, they will remain like that, while the 7 on the right side of the equation is eliminated.
x + 7 = 15y.
Now we are going to divide both sides by 15, thus leaving y by itself.
= 15y / 15.
Since we cannot divide the left side of the equation by 15, it will remain as such. With the y variable completely isolated, our final inverse function will be:
= .
Hopefully, this helps! =)
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.