Answered

IDNLearn.com connects you with a global community of knowledgeable individuals. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.

A patient requires an IV of D5W, a 5% solution of dextrose (sugar) in water. To the nearest milliliter, how much D20W, a 20% solution of dextrose in water, must be added to 100 milliliters of distilled water to produce a D5W solution? Please show all work.

Sagot :

Okpalawalter8idn

Answer:

  [tex]A=300ml[/tex]

Step-by-step explanation:

From the question we are told that

5% solution of dextrose sugar in water

20% solution of dextrose in

100 milliliters of distilled water water

Generally in mathematically solving we call A the amount of D20W added

Since 20% of dextrose is needed

       [tex]20 \%*100=20milliter[/tex]

Total quantity after addition (100+x)

for DW5% total solution is

          [tex]5\% (100+A)= \frac{5}{100}(100+A)[/tex]

          [tex]5\% (100+A) =5+0.05A[/tex]

Mathematically

           [tex]5+0.05A =20[/tex]

           [tex]5+0.05A =20-5[/tex]

           [tex]A=\frac{15}{0.05}[/tex]

           [tex]A=300ml[/tex]

Therefore the required quantity [tex]A=300ml[/tex]

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.