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What is the freezing point in °C) of a 0.195 m
aqueous solution of K2S?
Enter your rounded answer with
3 decimal places.
K for water = 1.86 °C/m

What Is The Freezing Point In C Of A 0195 M Aqueous Solution Of K2S Enter Your Rounded Answer With 3 Decimal Places K For Water 186 Cm class=

Sagot :

Sebassandinidn

Answer:

[tex]T_S=-1.09\°C[/tex]

Explanation:

Hello!

In this case, since the freezing point depression for a solution is computed via:

[tex](T_S-T_W)=-imK_f[/tex]

Whereas TW is the freezing temperature of water, TS that of the solution, i the van't Hoff's factor (3 for K2S as it ionizes properly), m the molality of the solution and Kf the freezing point constant of water. Thus, we plug in to obtain:

[tex](T_S-0\°C)=-3*0.195m*1.86\frac{\°C}{m}\\\\T_S=-1.09\°C[/tex]

Best regards!

The correct answer is -1.088. (Don't forget the negative sign).

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