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A 10 kg block is attached to a light cord that is wrapped around the pulley of an electric motor, as shown above. If the motor raises the block from the floor to a height of 8.0 meters in 5 seconds what was the motor’s power output?

A 10 Kg Block Is Attached To A Light Cord That Is Wrapped Around The Pulley Of An Electric Motor As Shown Above If The Motor Raises The Block From The Floor To class=

Sagot :

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Answer:

156.8 Watts

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 10 kg

Height (h) = 8 m

Time (t) = 5 s

Power (P) =?

Next, we shall determine the energy used by the motor to raise the block. This can be obtained as follow:

Mass (m) = 10 kg

Height (h) = 8 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

E = mgh

E = 10 × 9. 8 × 8

E = 784 J

Finally, we shall determine the power output of the motor. This can be obtained as illustrated below:

Time (t) = 5 s

Energy (E) = 784 J

Power (P) =?

P = E/t

P = 784 / 5

P = 156.8 Watts

Therefore, the power output of the motor is 156.8 Watts

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