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Sagot :
Answer:
[tex]\displaystyle x= 1\pm \sqrt{5}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Algebra I
- Standard Form: ax² + bx + c = 0
- Quadratic Formula: [tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
Step-by-step explanation:
Step 1: Define
x² - 2x - 4 = 0
Step 2: Identify Variables
a = 1
b = -2
c = -4
Step 3: Solve for x
- Substitute [QF]: [tex]\displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(1)(-4)} }{2(1)}[/tex]
- Exponents: [tex]\displaystyle x=\frac{2\pm\sqrt{4-4(1)(-4)} }{2(1)}[/tex]
- Multiply: [tex]\displaystyle x=\frac{2\pm\sqrt{4+16} }{2}[/tex]
- Add: [tex]\displaystyle x=\frac{2\pm\sqrt{20} }{2}[/tex]
- Simplify: [tex]\displaystyle x=\frac{2\pm 2\sqrt{5} }{2}[/tex]
- Factor: [tex]\displaystyle x=\frac{2(1\pm \sqrt{5}) }{2}[/tex]
- Divide: [tex]\displaystyle x= 1\pm \sqrt{5}[/tex]
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