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Given:
Dividend = [tex]2x^3-5x^2+x+2[/tex]
Divisor = [tex]x-2[/tex]
To find:
The quotient and remainder.
Solution:
We have,
Dividend = [tex]2x^3-5x^2+x+2[/tex]
Divisor = [tex]x-2[/tex]
Divide [tex]2x^3-5x^2+x+2[/tex] by [tex]x-2[/tex] as shown in the below picture.
Dividing [tex]2x^3-5x^2+x+2[/tex] by [tex]x-2[/tex], we get
[tex]Quotient=2x^2-x-1[/tex]
[tex]Remainder=0[/tex]
Therefore, [tex]Quotient=2x^2-x-1[/tex] and [tex]Remainder=0[/tex].
