IDNLearn.com makes it easy to find answers and share knowledge with others. Find in-depth and trustworthy answers to all your questions from our experienced community members.
Sagot :
Answer:
work energy equation
[tex]w.d(external)= \delta \: k.e+ \: \: \ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: w.d(ressesive)[/tex]
Explanation:
first of all we have to find reaction force to find fr
[tex]fr = \mu \: mg \\ mg = reaction \: force(r) \\ f = ma \\ r + 40 \sin(22) - 150 = 0 \\ r = 150 - 40 \sin(22) [/tex]
then let's find friction
[tex]fr = \mu \: r \\ 0.2 \times (150 - 40 \sin(22) )[/tex]
then let's apply work energy principle...its on the 2nd picture
v = 2.3ms^-1


We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.