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In ΔCAB, if m∠A = 10x + 9, m∠B = 34°, and m∠C = 97°, what is the value of x?


triangle CAB, point E is on segment AC between points A and C and point D is on segment BC between points B and C, creating segment ED


x = 2

x = 3

x = 4

x = 5


Sagot :

Answer:

x = 4

Step-by-step explanation:

(10x + 9) + 34 + 97 = 180

10x +140 = 180

10x = 40

x = 4

The value of x in the given angles of the traingle CAB for angle m∠A is determined as 4.

Sum of angles in a triangle

The sum of angles in a triangle can be used to determine the value of x in the given angles above.

m∠A + m∠B + m∠C  = 180 (sum of angles in a triangle)

10x + 9 + 34 + 97 = 180

10x + 140 = 180

10x = 40

divide both sides by 10;

x = 40/10

x = 4

Thus, the value of x in the given angles of the traingle CAB for angle m∠A is determined as 4.

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