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Sagot :
Answer:
Isosceles triangle
Step-by-step explanation:
Length of side AB = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
= [tex]\sqrt{(-11+3)^2+(2-6)^2}[/tex]
= [tex]\sqrt{64+16}[/tex]
= [tex]\sqrt{80}[/tex]
= 4[tex]\sqrt{5}[/tex]
Length of BC = [tex]\sqrt{(-4+11)^2+(-2-2)^2}[/tex]
= [tex]\sqrt{49+16}[/tex]
= [tex]\sqrt{65}[/tex]
Length of AC = [tex]\sqrt{(-3+4)^2+(6+2)^2}[/tex]
= [tex]\sqrt{1+64}[/tex]
= [tex]\sqrt{65}[/tex]
Since, AC = BC, ΔABC will be an isosceles triangle.
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