Answered

IDNLearn.com: Where your questions meet expert advice and community insights. Ask your questions and get detailed, reliable answers from our community of experienced experts.

How many moles of NaCl are present in 2.50 L of a 0.070 M solution?


a

2.8 x 10-2 moles of NaCl


b

35.7 moles of NaCl

c

1.75 x 10-4 moles of NaCl


d

0.175 moles of NaCl

Sagot :

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

[tex]M = \dfrac{n}{V(in\ L)}[/tex]

So,

[tex]n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles[/tex]

Therefore, number of moles of NaCl is 0.175 moles.

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.