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How many moles of NaCl are present in 2.50 L of a 0.070 M solution?


a

2.8 x 10-2 moles of NaCl


b

35.7 moles of NaCl

c

1.75 x 10-4 moles of NaCl


d

0.175 moles of NaCl

Sagot :

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

[tex]M = \dfrac{n}{V(in\ L)}[/tex]

So,

[tex]n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles[/tex]

Therefore, number of moles of NaCl is 0.175 moles.

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