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Answer:
Q ≅ 1.53 m³/s
Explanation:
From the given information:
The flow rate of the orifice is:
[tex]v = c_v \sqrt{2gh}[/tex]
[tex]v = 0.90 \times \sqrt{2*9.81 * 10}[/tex]
where;
[tex]Q = c_d \times \sqrt{2gh} \times A[/tex]; &
[tex]c_d = c_c \times c_v[/tex]
∴
[tex]Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2[/tex]
[tex]Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2[/tex]
[tex]Q = 0.558 \times 14.00714104 \times 0.1963495408[/tex]
Q ≅ 1.53 m³/s