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Matthew has a jar of 368 nickels and dimes he has been collecting. The total value of the coins is $28.40.Which system of linear equations and solution can be used to represent the number of nickels and dimes Matthew has in his collection?


A. n + d = 368 0.05n + 0.1d=28.4 168 nickels and 200 dimes

B. n + d = 368 0.01n + 0.05d=28.4 200 nickels and 168 dimes

C. n + d = 368 0.05n + 0.1d=28.4 200 nickels and 168 dimes

D. n + d = 368 0.1n + 0.05d=28.4 168 nickels and 200 dimes


Sagot :

Answer:

[tex]n + d = 368[/tex]

[tex]0.05n + 0.10d = 28.40[/tex]

Step-by-step explanation:

Given

[tex]Total = 368[/tex]

[tex]Value = \$28.40[/tex]

Required

Determine the linear equations to represent the scenario

Represent nickel with n and dimes with d

So, the total is:

[tex]n + d = 368[/tex]

[tex]1\ nickel = \$0.05[/tex]

[tex]1\ dime = \$0.10[/tex]

So, the value is:

[tex]0.05n + 0.10d = 28.40[/tex]

Hence, the linear equations are:

[tex]n + d = 368[/tex]

[tex]0.05n + 0.10d = 28.40[/tex]

The system of linear equations and solution can be used to represent the number of nickels and dimes Matthew has in his collection is n + d = 368 0.05n + 0.1d=28.4  168 nickels and 200 dimes.

Given that,

  • Matthew has a jar of 368 nickels and dimes he has been collecting.
  • The total value of the coins is $28.40.
  • Here we take n be nickles and d be dimes.
  • Also, 1 nickel be = $0.05 and 1 dime be $0.10.

Based on the above information, the calculation is as follows:

n + d = 368

So,

d = 368 - n

And,

0.05n + 0.10d = 28.40

0.05n + 0.10(368 - n) = 28.40

0.05n + 36.8 - 0.10n = 28.40

0.05n = 8.4

n = 168

So, d = 368 - 168

= 200

Therefore we can conclude that the correct option is A.

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