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Answer:
The force per unit length of the wire is 6 x 10⁻⁵ N/m.
Explanation:
Given;
distance between the two parallel wires, r = 4 cm
current in the first wire, I₁ = 2 A
current in the second wire, I₂ = 6 A
The force per unit length of the wire is calculated as;
[tex]\frac{f}{l} = \frac{\mu I_1 I_2}{2\pi r} \\\\\frac{f}{l} =\frac{4\pi \times 10^{-7} \ \times \ 2 \ \times \ 6}{2\pi \ \times \ 0.04} \\\\\frac{f}{l} = 6 \ \times \ 10^{-5} \ N/m\\\\[/tex]
Therefore, the force per unit length of the wire is 6 x 10⁻⁵ N/m.